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My SQL UPDATE with subqueries Here in the following, we have discussed how to use My SQL UPDATE command with subqueries.The following My SQL statement will update purch_price with purch_price multiplied by 5 if it satisfies the condition defined in the subquery started with SELECT wrapped within a pair of parenthesis.php // connect to the database and select the correct database mysql_connect(localhost,username,password); mysql_select_db(db_name) or die("Unable to select database"); // find out how many records there are to update $size = count($_POST['Avalibity']); // start a loop in order to update each record $i = 0; while ($i < $size) mysql_close(); ?> <tr> <td colspan='4' align='center'> </td> </tr> </table> </td> </tr> </table></div></body></html> been one of my strong points.In this statement, other columns are also updated with respective new values.My SQL UPDATE multiple columns My SQL UPDATE command can be used to update multiple columns by specifying a comma separated list of column_name = new_value.My SQL UPDATE with WHERE My SQL UPDATE command can be used with WHERE clause to filter (against certain conditions) which rows will be updated.The following My SQL statement will update the 'receive_qty' column of newpurchase table with a new value 25 if the value of purch_price is more than 50.
We have used a table called 'item' to apply the query: Table Name : item Structure : item_code varchar(20), value int(11), quantity int(11) where item_code is the primary key.
Regards, Tomas Helgi I'm not a mysql guy so that syntax might be iffy, but I thought it was correct.
I don't see any logic in this and I believe that this could produce strange issues like this you are dealing with.
The subquery retrieves only those cate_ids from purchase table if their corresponding receive_qty is more than 10.
Updating My SQL Table using PHP Script You can update My SQL table data (using UPDATE command) through a PHP script.
She'll teach 12 steps that you can use to optimize your queries as much as possible and see measurable results in your work. if an alias is all it needs that's easy to fix UPDATE entity t SET address = (SELECT CEIL((@i := @i 1) / 3) FROM (SELECT name FROM entity order by referencekey) s ,(select @i := 0) where = ) x where name like 'A01%TYPE%E%'; Thanks for the reply Tomas Helgi. This code here (select @i := 0) , what is your idea with that ?